# insertAll method

void insertAll (int index, Iterable<E> iterable)
override

Inserts all objects of `iterable` at position `index` in this list.

This increases the length of the list by the length of `iterable` and shifts all later objects towards the end of the list.

An error occurs if the `index` is less than 0 or greater than length. An UnsupportedError occurs if the list is fixed-length.

## Implementation

    void insertAll(int index, Iterable<E> iterable) {
      RangeError.checkValueInInterval(index, 0, length, "index");
      if (iterable is! EfficientLengthIterable || identical(iterable, this)) {
        iterable = iterable.toList();
      }
      int insertionLength = iterable.length;
      // There might be errors after the length change, in which case the list
      // will end up being modified but the operation not complete. Unless we
      // always go through a "toList" we can't really avoid that.
      this.length += insertionLength;
      if (iterable.length != insertionLength) {
        // If the iterable's length is linked to this list's length somehow,
        // we can't insert one in the other.
        this.length -= insertionLength;
        throw new ConcurrentModificationError(iterable);
      }
      setRange(index + insertionLength, this.length, this, index);
      setAll(index, iterable);
    }